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E = hv: explanation
E = hv: APPLICATION
a Photon's Wavelength (λ) and energy E are linked through the following equation:
E = hc/λ
WHERE:
h = Planck's constant = 6.63 x 10 J s (Joules per second)
v = frequency of the radiaiton
c= speed of light
E is inversely proportional to λ.
"Example 1"
Determine the energy, in J of a photon of red light, correct to four significant figures, given that the wavelength λ. = 650.0 nm.
h = 6.626 x 10^ -34 J s; c = 2.998 x 10 ^8 m s^-1
SOLUTION
ΔE = hv = hc/λ
ΔE = 6.626 X 10 ^-34 J s x 2.988 x 10 ^8 m s^-1
650.0 x 10^-9m = 3.056 x 10 ^-19 J
EXAMPLE 2
Calculate the first ionization energy, in KJ mol ^-1, for hydrogen given that its shortest wavelength line in the Lyman series is 91.16 nm.
h= 6.626 x 10 ^-34 J s; c = 2.998 x 10^ 8 m s ^-1; N A mol ^-1
SOLUTION
The shortest wavelenght line in the lyman serie scorresponds to a transition of n = ∝ to n = 1
IE1 = hv = hc/λ
IE1 = 6.626 x 10 ^-34 J s x 2.998 x 10^8 m s^ -1
91.16 x 10 ^-9 m = 2.179 x 10 ^-18 J
Expressed in kJ mol ^ -1
IE1 = (2.179 x 10 ^-18 J ) x (6.022 x 10^23 mol ^-1 ) = 1.312 x 10 ^ 6 mol ^-1
= 1312 kJ mol ^-1